method-signature-style
Enforce using a particular method signature syntax.
There are two ways to define an object/interface function property.
// method shorthand syntax
interface T1 {
func(arg: string): number;
}
// regular property with function type
interface T2 {
func: (arg: string) => number;
}
A good practice is to use the TypeScript's strict
option (which implies strictFunctionTypes
) which enables correct typechecking for function properties only (method signatures get old behavior).
TypeScript FAQ:
A method and a function property of the same type behave differently. Methods are always bivariant in their argument, while function properties are contravariant in their argument under
strictFunctionTypes
.
See the reasoning behind that in the TypeScript PR for the compiler option.
Attributes
- Included in configs
- ✅ Recommended
- 🔒 Strict
- Fixable
- 🔧 Automated Fixer
- 💡 Suggestion Fixer
- 💭 Requires type information
module.exports = {
"rules": {
"@typescript-eslint/method-signature-style": "warn"
}
};
Options
This rule accepts an options string of the following possible values:
type Options = "property" | "method";
const defaultOptions: Options = ["property"];
This rule accepts one string option:
"property"
: Enforce using property signature for functions. Use this to enforce maximum correctness together with TypeScript's strict mode."method"
: Enforce using method signature for functions. Use this if you aren't using TypeScript's strict mode and prefer this style.
The default is "property"
.
property
Examples of code with property
option.
- ❌ Incorrect
- ✅ Correct
interface T1 {
func(arg: string): number;
}
type T2 = {
func(arg: boolean): void;
};
interface T3 {
func(arg: number): void;
func(arg: string): void;
func(arg: boolean): void;
}
interface T1 {
func: (arg: string) => number;
}
type T2 = {
func: (arg: boolean) => void;
};
// this is equivalent to the overload
interface T3 {
func: ((arg: number) => void) &
((arg: string) => void) &
((arg: boolean) => void);
}
method
Examples of code with method
option.
- ❌ Incorrect
- ✅ Correct
interface T1 {
func: (arg: string) => number;
}
type T2 = {
func: (arg: boolean) => void;
};
interface T1 {
func(arg: string): number;
}
type T2 = {
func(arg: boolean): void;
};
When Not To Use It
If you don't want to enforce a particular style for object/interface function types, and/or if you don't use strictFunctionTypes
, then you don't need this rule.